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**Maths Shortcut and Mind Trick for Solving Ratio and Proportion Problems**

Hello
Friends, Today we are sharing a Mind Trick based on Ratio & Proportion
question. Hope, you will like it. And you can download this trick in PDF
Format. The Download link is given below in this article.

Q)
If in a bag Rupee 1, 50 p and 10 p coins are present in the ratio as 5:8:10
amounting to Rs.400. Then find the total number of 10paise coins present in the
bag?

We are given
Following Information:

Denomination
of coins Present in the bag = 50p, 10p, 1 Rupee

Total Amount
= Rs 400

Ratio of
coins = 5 : 8 : 10

Solution:

First we solve this question by

**Normal Method:**
As we Know, 1 Rupee= 100 Paise

Therefore, Let the total number of 1Rupee (100 p), 50p, 10p coins present
are 5x, 8x and 10x respectively.

As the total amount we are given in the above question in Rupees i.e
Rs 400.

Therefore First we have to convert the denomination of 50p and 10p
into Rupee denomination.

As, 100 P =
1Rupee

1 P = 1/100 Rupee

50
P = (1/100)* 50 Rupee= ½ Rupee

Similarly,
10 P = [(1/100)* 10] Rupee = [1/10] Rupee

Also, 1
Rupee= 1 Rupee

Now, Multiply
the converted rupees value with the respected given ratios,

Therefore,
We get

=1×5x + (½ ×8x)
+ [(1/10)×10x]

=5x+(4x)+(x)

=10x

According to
Given Question,

10x = 400

x = [400/10]
= 40

Now, We have to find the total number of 10p coins present in the
bag.

Therefore, No. of 10p coins present in the bag = 10x = [10×40] = 400
coins

*Therefore, 400 Coins is the required answer.*
Now
we will solve this question direct by

**Shortcut method:**As we have: 5×100p: 8×50p: 10×10p

Therefore, Sum
of all Parts= 10

And 10= Rs.400

So, One part
of x = ?

x = Rs. 400
/10 = 40

There for total
no. of 10p coins = 10×40

= 400 coins.

Thank You Friends!! J

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