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**Tips to Solve Classification Based Questions of Reasoning Section**

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Hello friends, today we are
sharing some tips to solve the questions related to classification topic of
reasoning section.

So first of all we should
know, what

**CLASSIFICATION**means for?
· Classification
is a term used to arrange the given items of a group on the basis of a some common
quality they posses and find the odd one out.

· These types
of questions consists a group of 4 or 5 items out of which one would possess some
different quality, have some different pattern & rest of the given items
would be similar in a certain relationship among themselves.

·
So, we have
to find that odd item in a group.

·
Normally,
two-types of questions can be expected from this topic:

Ã˜
Alphabetical
series

Ã˜
Number
series

Alphabetical Series:

In these types of questions,
we will be provided with five groups of words, out of which we have to find the
odd word which possess different quality or pattern from the other words of the
similar group.

**Hints that you can look for:**

·
Presence of vowels.

· Check the number of alphabets in between the letters in each group
both in forward and reverse direction as present in the English alphabet series.

**Let us take an example:**

Q) Four of the following
five are alike in a certain way and hence form a group. Find the

one that does not belong
to the group?

(a) OPQ (b) EFG (c) VWG
(d) ABC (e) IJK

Solution:

First
look for the vowels.

All the given options a, b, d & e consists of a vowel OPQ, EFG, ABC, IJK. Only option c consists of consonents.

Therefore, option ‘c’ VWG is
the odd one out & will be the required answer.

Q) Find the one does not
belong to the group?

(a) SVZ (b) DFH
(c) JLN (d)NPR (e) VXZ

Solution: As
there are no vowels present in the given
options. Therefore
now we can look for the number of alphabets present between each letter in the
Eglish alphabetical series

S V Z D F H
J L N N P R
V X Z

2 3 1 1 1 1 1 1 1 1

As
clear from the above pattern that all the given options b, c, d & e
have a difference of one letter between them, thus forming a group, only option
(a) have a difference of 2-letter ‘TU’ between S and V & a difference of 3-letters
‘WXY’ between V and Z

Therefore, option (a) SVZ
will be the required answer.

Number Series:

To find the odd one out from
the given numbers we can use the following hints to find the solution. Check
whether the given numbers are:

1) Divisible by some number

2) Odd number group

3) Even number group

4) Prime number

5) Square roots

6) Cube roots

7) Square ± number

8) Cube ± number

9) Sum of digits

Q) Find the one does not
belong to the group?

(a) 37 (b) 26 (c) 325 (d)
35 (e) 226

Solution:

By analysing for the pattern
we find that, the numbers in the options are in the (Square ± number) form:

37 = 62 +
1

26 = 52 +1

325 = 182+1

35 = 62 –
1

226
= 152+1

Therefore, option (d) 35 will be the required answer.

Thank you Friends !! J

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