Showing posts with label Maths Notes. Show all posts
Showing posts with label Maths Notes. Show all posts

How to Find Square Root of a Number Easily and Quickly - Maths Tricks on Square Root of any number in Hindi

How to Find Square Root of a Number Easily and Quickly?

Square Root Trick in Hindi


Many of Us Know the typical and traditional lengthy method related to how to Find Square root of a number. In this article, we are going to discuss with you readers how to Calculate square root easily and quickly by using a Maths trick. As we are sharing time to time new and free maths video tutorial with you readers in this Sarkari Job Portal Channel, this time we are going to show you ‘how to finds Square root of Any Number’ by using a simple maths trick.

how to find square root of a number

AAA-Bright Academy is one of the best Bank Po, SSC Exam coaching centre in Chandigarh city. One of the Experts and experienced Teacher of AAA-Bright Academy sharing an easy way to find the square root of a number. Square root method in Hindi language for all candidates who are preparing for any entrance examination.

After watching this Maths Video tutorial we are 100% sure that you will come to know how to find square root of a number quickly and easily. Watch this Maths trick video tutorial till the end to understand the complete concept related to this Square root tricks method.

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Time, Work and Wages Problems For Bank Exam - Work and wages Concept and Shotcut

Time, Work and Wages Problems For Bank Exam

Quantitative Aptitude Study Notes for Bank Exam
Complete work and wages concept
work and wages Shortcut
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in math's. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams as well as in other competitive exams. That’s where maths shortcut tricks and formula are comes into action. 
Time, Work and Wages Problems For Bank Exam

So continuously we are providing shortcut tricks on different maths topics. Today’s topic is time and wages problems for bank exam. This is the one of the most important topic in quantitative aptitude section in bank and SSC exam. You should know how to solve time and wages questions in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to solve time, work and wages problems in very short time. This topic is similar to the time and work problems topic but the only difference is that in this topic we will also find out wages of the workers according to their time for that particular work. Time and wages formulas: If ‘M1’ persons can do ‘W1’ work in ‘D1’ days and ‘M2’ persons can do ‘W2’ work in ‘D2’ days then we have a very special general formula in the relationship of M1 D1 W2 = M2 D2 W1.

Time and Work Problems For Bank Exam

Time and Work Problems For Bank Exam

Quantitative Aptitude Study Notes for Bank Exam
Time and Work Problems For Bank Exam
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams as well as in other competitive exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics. Today’s topic is time and work problems for bank exam. This is the one of the most important topic in quantitative aptitude section in bank and SSC exam. You should know how to solve time and work questions in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to solve time and work problems in very short time. Before going to solve questions for time and work, we study little bit about basics and formulas for time and work. If ‘M1’ persons can do ‘W1’ work in ‘D1’ days and ‘M2’ persons can do ‘W2’ work in ‘D2’ days then we have a very special general formula in the relationship of M1 D1 W2 = M2 D2 W1. The above relationship can be taken as a very basic and all-in-one formula. We also derive:

Compound Interest Problems For A Bank Exam

Compound Interest Problems For A Bank Exam

 Quantitative Aptitude Study Notes for Bank Exam
Compound Interest Problems For A Bank Exam
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams as well as in other competitive exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics. Today’s topic is Compound Interest. This is the one of the most important topic in quantitative aptitude section in bank and SSC exam. You should know how to compound interest problems in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to solve compound interest problems in very short time.  Interest is the money paid by the borrower to the lender for the use of money lent. The sum lent is called the principal. Interest is usually calculated at the rate of so many rupees for every Rs 100 of the money lent for a year. This is called the rate per cent per annul.

Simple Interest Quantitative Aptitude Study Notes for Bank Exam

Simple Interest Quantitative Aptitude Study Notes for Bank Exam
Simple Interest Quantitative Aptitude Study Notes for Bank Exam
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams as well as in other competitive exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics. Today’s topic is Simple Interest. This is the one of the most important topic in quantitative aptitude section in bank and SSC exam. You should know how to simple interest questions and answers in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to solve simple interest problems in very short time.  Interest is the money paid by the borrower to the lender for the use of money lent. The sum lent is called the principal. Interest is usually calculated at the rate of so many rupees for every Rs 100 of the money lent for a year. This is called the rate per cent per annum.

PROBABILITY (Introduction and Concepts)

PROBABILITY (Introduction and Concepts)

Quantitative Aptitude Study Notes for Bank & SSC Exam
PROBABILITY (Introduction and Concepts)
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams as well as in other competitive exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics. Today’s topic is Probability. This is the one of the most important topic in quantitative aptitude section in bank and SSC exam. You should know how to probability questions and answers in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to solve probability problems in very short time. It is similar to previous topic permutations and combinations.

PERMUTATIONS AND COMBINATIONS

PERMUTATIONS AND COMBINATIONS
Quantitative Aptitude Study Notes for Bank & SSC Exam
PERMUTATIONS AND COMBINATIONS
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams as well as in other competitive exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics. Today’s topic is Permutations and combinations. This is the one of the most important topic in quantitative aptitude section in bank and SSC exam. You should know how to Permutations and combinations questions and answers in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to solve permutations and combinations problems in very short time.

BOATS AND STREAMS QUANTITATIVE APTITUDE STUDY NOTES

BOATS AND STREAMS QUANTITATIVE APTITUDE STUDY NOTES

FOR BANK AND SSC EXAM
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics.
BOATS AND STREAMS QUANTITATIVE APTITUDE STUDY NOTES
Today’s topic is BOATS AND STREAMS; this is the one of the most important topics in quantitative aptitude section in Bank and SSC exam. You should know how to calculate Boats and stream questions and answers in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to calculate BOATS AND STREAMS in very short time. We also providing the theorems which are elaborate short trick formula’s for stream boat.
Introduction to Boats and Streams: Normally, by speed of the boat or swimmer we mean the speed of the boat or swimmer in still water. If the boat ( or swimmer ) moves against the stream then it is called upstream and if it moves with the stream, it is called downstream.
If the speed of the boat (or the swimmer) is x and if the speed of the stream is y then, while upstream the effective speed of the boat = x – y and while downstream the effective speed of the boat = x + y.
Here are the theorems and formula’s with short tricks for boats and streams:
Theorem 1:
if x km per hour be the man’s rate in still water, and y km per hour the rate of the current.  Then
x + y = man’s rate with current
x – y = man’s rate against current.
Adding and subtracting and then dividing by 2.
x = ½ ( man’s rate with current + his rate against current)
y = ½ ( man’s rate with current – his rate against current)

hence, we have the following two facts:
(i)                A man’s rate in still water is half the sum of his rates with and against the current.
(ii)              The rate of the current is half the difference between the rates with and against the current.
Ex. 1: A man can row upstream at 10 km/hr and downstream at 16 km/hr. Find the man’s rate in still water and the rate of the current.
Solution: Rate in still water = ½ (10 + 6) = 13 km/hr
Rate of current = ½ (16 – 10) = 3 km/hr
Ex. 2: A man swims downstream 30 km and upstream 18 km, taking 3 hrs each time. What is the velocity of current?
Solution: Man’s rate downstream = 30/3 km/hr = 10 km/hr
Man’s rate upstream = 18/3 km/hr = 6 km/hr
Velocity of stream = (10 – 6) / 2
= 2 km/hr
Ex. 3: A man can row 6 km/hr in still water. It takes him twice as long to row up as to row down the river. Find the rate of the stream.
This questions we can solve by three methods, we will discuss one by one;
Solution: method 1:
Let man’s rate upstream = x km/hr
Then, man’s rate downstream = 2x km/hr
Man’s rate in still water = ½ (x + 2x) km/hr
3x/2 = 6
Or x = 4 km/hr
Thus, man’s rate upstream = 4 km/hr
Man’s rate downstream = 8 km/hr
Rate of stream = ½ (8 – 4) = 2 km/hr

Method 2:
We have,
Up rate + down rate = 2 * rate in still water
= 2 * 6 = 12 km/hr
Also, up rate: down rate = 1:2
So, dividing 12 in in the ration of 1: 2, we get
Up rate = 4 km/hr
Down rate = 8 km/hr
Rate of stream = 8 – 4 / 2
= 2 km/hr
Method 3 (shortest Method): let the rate of stream = x km/hr
Then,
 6 + x = 2 (6-x)
Or, 3x = 6
X = 6/3 = 2 km/h
Theorem 2: for boats and streams:
A man can row x km/hr in still water. If in a stream which is following at y km/hr, it takes him z hrs to row to a place and back, the distance between the two places is z(x2 – y2 ) / 2x
Proof: man’s speed up stream = (x – y) km/hr
Man’s speed downstream = (x + y ) km/hr
Let the required distance be ‘A’ km then
BOATS AND STREAMS QUANTITATIVE APTITUDE STUDY NOTES

Or, 2Ax / x2 – y2 = z
The required distance = z(x2 – y2) / 2x

Ex. 4: A man can row 6 km/hr in still water. When the river is running at 1.2 km/hr, it takes him 1 hour to row to a place and back. How far is the place?
Solution: Man’s rate downstream = (6 + 1.2) km/hr = 7.2 km/hr
Man’s rate upstream = (6 – 1.2) km/hr = 4.8 km/hr
Let the required distance be x km. Then
x/7.2 + x/4.8 = 1
or 4.8x + 7.2x = 7.2 * 4.8
x = 7.2 * 4.8 / 12
= 2.88 km.
By direct formula: required distance = 1*(62 – (1.2)2) / 2*6
36 – 1.44 / 12
3 – 0.12
=2.88 km.
Theorem 3: for boats and streams:
A man rows a certain distance downstream in x hours and returns the same distance in y hrs. If the stream follows at the rate of z km/hr then the speed of the man  in still water is given by
Z(x+y) / y-x km/hr.

Proof: let the speed of the man in still water be ‘m’ km/hr.
Then, his upstream speed = (m - z) km/hr.
And downstream speed = (m + z) km/hr/
Now, we are given that up and down journey are equal, therefore x(m + z) = y(m – z)
Or, m(y-x) = z(x+y)
M = z(x + y) / y – x km/hr
Ex. 5: Ramesh can row a certain distance downstream in 6 hours and return the same distance in 9 hours. If the stream flows at the rate of 3 km per hour, find the speed of Ramesh in still water.
Solution:
By the above formula: Ramesh’s speed in still water = 3(9+6) / 9-6 km/hr.

For quantitative aptitude study notes on other topics CLICK HERE

For Bank and SSC exam study notes CLICK HERE

QUANTITATIVE APTITUDE AGE PROBLEMS

AGE PROBLEMS WITH SOLUTIONS QUANTITATIVE APTITUDE STUDY NOTES FOR BANK AND SSC EXAM

You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics.
AGE PROBLEMS
Today’s topic is AGE PROBLEMS. This is the one of the most important topic in quantitative aptitude section in bank and ssc exam. You should know how to calculate Age problems questions and answers in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing maths shortcut tricks and quicker method to calculate quantitative apptitude questions in very short time.

PIPES AND CISTERNS

Quantitative Aptitude Study Notes for Bank & SSC Exam
PIPES AND CISTERNS
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics.
PIPES AND CISTERNS
 Today’s topic is PIPES AND CISTERNS. This is the one of the most important topic in quantitative aptitude section in bank and ssc exam. You should know how to calculate pipe and cisterns questions and answers in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to calculate pipe and cisterns in very short time.

TIME DISTANCE AND TRAINS

Quantitative Aptitude Study Notes

BANK AND SSC EXAM

TIME DISTANCE AND TRAINS
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics.
TIME DISTANCE AND TRAINS
Today’s topic is TIME DISTANCE AND TRAINS, it is similar to time and distance topic which we have covered in our recent topic. This is the one of the most important topic in quantitative aptitude section in bank and ssc exam. You should know how to calculate trains questions and answers in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to calculate TIME DISTANCE AND TRAINS in very short time.

TIME AND DISTANCE

Quantitative Aptitude Study Notes 
 Bank & SSC Exam

TIME AND DISTANCE
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics.
TIME AND DISTANCE
 Today’s topic is TIME AND DISTANCE. This is the one of the most important topic in quantitative aptitude section in bank and ssc exam. You should know how to calculate time and distance questions and answers in very short time for bank exam. From this chapter around 1-2 questions are given in the SBI and IBPS exams. For this here we are providing shortcut tricks and quicker method to calculate time and distance in very short time.
If we want to solve time and distance questions or any other type of questions, then the first thing that we need that is Formulas about that topic. So here is the list of formulas that is used in time and distance quantitative topic.

PROFIT AND LOSS (Profit and loss questions for Bank exams)

Quantitative Aptitude Study Notes 
 Bank & SSC Exam

PROFIT AND LOSS

Profit and loss questions for bank exams. You know that the quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want a good score in the bank exam then you have to score well in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams. That’s where maths shortcut tricks and formula are comes into action. So continuously we are providing shortcut tricks on different maths topics.

One of the most important topics in maths is PROFIT AND LOSS for Competetive Exams. You should know how to calculate profit and loss in a very short time. For this here we are providing shortcut tricks and quicker methods to calculate profit and loss in maths.

PROFIT AND LOSS
For profit and loss, we use the rule of the fraction is dominant. We should understand this rule very well because it is going to be used in almost all the questions.

If our required value is greater then the supplied value, we should multiply the supplied value with a fraction which is more than one. And if our required value is less than the supplied value, we should multiply the supplied value with a fraction that is less then one.
If there is a gain of x%, the calculating figures would be 100 and (100 + x).
If there is a loss of y%, the calculating figures would be 100 and (100 - y).
If the required value is more than the supplied value, our multiplying fractions should be 100 + x / 100
Or
100 / 100 – y
(both are greater than 1).
If the required value is less than the supplied value, our multiplying fractions should be
Fractions should be 100 / 100 + x
Or
100 – y / 100
(Both are less than 1).

PROFIT = SELLING PRICE (SP) – COST PRICE (CP)
LOSS = COST PRICE (CP) – SELLING PRICE (SP)
To find the gain or loss percent %
The profit or loss is generally reckoned as so much percent on the cost.
GAIN OR LOSS PER CENT % = loss or gain × 100 / CP

AVERAGE SHORTCUT : Calculate Average with a Trick

CALCULATE AVERAGE SHORTCUT TRICKS

You know that the quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want a good score in the bank exam then you have to score well in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams. That’s where maths shortcut tricks and formulas are comes into action. So continuously we are providing shortcut tricks on different maths topics.
One of the most important topics in maths is average. You should know how to calculate the Average in a very short time. For this here we are providing shortcut tricks to calculate averages in maths.

CALCULATE AVERAGE SHORTCUT TRICKS


AVERAGE: An average, or more accurately an arithmetic mean is, in crude terms, the sum of n different data divided by n.

HOW TO CALCULATE THE AVERAGE:
For example, if a batsman scores 30, 50, and 25 runs in the first, second, and third innings respectively, then his average runs in 3 innings is equal to
30+50+25/3; =39 runs

Therefore, the two most used formulas in this question are:
Average= total of data/no. of data
And total = average × no. of data

Important Formulae Related to Calculate Average of numbers:
1. Average of first n natural number = (n+1)/2
2. Average of the first n even number = (n+1)
3. Average of first n odd number = n
4. Average of consecutive number = (First number +Last number)/2
5. Average of 1 to n odd numbers = (Last odd number+1)/2
6. Average of 1 to n even numbers = (Last even number+2)/2
7. Average of squares of first n natural numbers = [(n+1) (2n+1)]/6
8. Average of the cubes of first n natural number = [n (n+1) ^2]/4
9. Average of n multiples of any number = [Number*(n+1)]/2

Examples with shortcut tricks on how to calculate Average are given below:
1. Ex: the average age of 30 boys in a class is equal to 14 yrs. When the age of the class teacher is included the average becomes 15 yrs. Find the age of the class teacher?
Solution: total ages of 30 boys = 14 × 30 = 420yrs.
Total ages when class teacher is included = 15 × 31 = 465yrs.
So the age of the class teacher = 465 – 420 = 45 yrs.
Shortcut trick: age of new entrant = new average + no. of old members × Increase in average = 15 + 30 (15-14) = 45 yrs.

2. Ex: the average weight of 4 men is increased by 3 kg when one of them who weighs 120kg is replaced by another man. What is the weight of the new man?
Solution: by shortcut trick: if the average is increased by 3 kg, then the sum of weight increases by 3 × 4 = 12 kg.
And this increase in weight is due to the extra weight included due to the inclusion of new person.
So weight of new man = 120 + 12 = 132 kg.
We can also solve this question by Direct formula: weight of new person = weight of removed person+ no. of persons × increase in average = 120 + 4 * 3= 132 kg.

3. Ex: the average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed the examination?
Solution: Let the number of passed candidates be x.
The total marks = 120 × 35 = 39x + (120-x) * 15
Or, 4200 = 39x + 1800 – 15x
Or, 24x = 2400
X = 100
So the number of passed candidates = 100.

We can also solve this question by shortcut trick direct formula:
Number of passed candidates =
total candidates ( total average – failed average) / passed the average-failed average
And the number of failed candidates=
Total candidates (passed average – total average) / passed average – failed average
by this, we can solve the number of passed candidates = 120 (35 – 15) / 39 – 15
                                                                                          = 100

4. Ex: A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after 17 innings?
Solution: let the average after 16th innings be x, then 16x + 85
= 17 (x + 3) = Total score after 17th innings.
X = 85 – 51 = 34
Average after 17 innings = x + 3 = 34 + 3 = 37
Shortcut tricks or direct formula:
Average after 16 innings = 85 – 3 * 17 = 34
Average after 17 innings = 85 – 3 (17 – 1) = 37.

5. Ex: a cricketer has completed 10 innings and his average is 21.5 runs. How many runs must he make in his next innings so as to raise his average to 24?
Solution: total of 10 innings = 21.5 × 10 = 215
Suppose he needs a score of x in 11th innings; then average in 11 innings = 215 + x / 11 =24
Or x, = 264 – 215 = 49
Shortcut tricks or direct formula:
Required score = 11 × 24 – 21.5 × 10 = 49
Note: the above formula is based on the theory that the difference is counted due to the score in the last innings.

6. Ex: in a class, there are 20 boys whose average age is decreased by 2 months, when one boy aged 18 years is replaced by a new boy. Find the age of the new boy.
Solution: Shortcut trick:
Age of new person = age of removed person – no. of persons × decrease in average age
= 18 – 20 × 2/12
= 18 – 10/3
= 44/3
= 14 yrs 8 months.

Also, read maths study notes & shortcut tricks on these topics:



MATH PERCENTAGE % SHORTCUT TRICKS

Quantitative Aptitude Study Notes for Bank & SSC Exam
MATH PERCENTAGE % SHORTCUT TRICKS
You know that quantitative aptitude section is most important in bank exams in PO and Clerk and for other competitive exams because if you want good score in bank exam then you have to score good in maths. In competitive exams the most important thing is time management, if you know how to manage your time then you can do well in Bank Exams. That’s where maths shortcut tricks and formula are comes into action.
The one of the most important topic in maths is Percentage %. You should know how to calculate maths percentage in very short time. For this here we are providing shortcut tricks to calculate percentage in maths.
MATH PERCENTAGE % SHORTCUT TRICKS

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